Now that we have checked out conditions for inference, we can calculate the two aspects that are necessary for a significance test: our test statistics and p-value.
The first and necessary aspect of our calculations is calculating our t-score. Since we are dealing with quantitative data (means), we need to find our degrees of freedom first.
To calculate our critical value, we used the typical formula:
To make it more specific for a t-score with the difference of two population means, our formula simplifies to:
This can be found on the
Formula Sheet by simplifying the given formulas.
Now that we know our appropriate degrees of freedom and our t-score, we can refer to our
Formula Sheet and refer to the appropriate row for our df. Looking across the tow, find the t-score value that is closest to the one you calculated for the t-score. Use the tail probability that most closely coordinates to your t-score.
A more exact way of calculating the p-value is to perform a 2 sample t-test in some form of technology such as a graphing calculator. As with any t-procedure, you are given the option of typing in the statistical information or entering in the data in list 1.
Once you enter the test in, the output gives you the t-score, df and p-value for your test. On the AP test, it is essential that you write down ALL 3 of these on your response to receive full credit.
For our green bean example from
Unit 7.8, this is what our input would look like:
And our output would be as follows:
Now that you have the numbers you need, you can check the statistical claim of the null hypothesis.
As with any significance test, we are checking to see if our p is lower than the significance level. If our p is low, we reject the null with convincing evidence of the alternate hypothesis. If the p is not lower than the significance level, we fail to reject the null hypothesis.
Once you make your decision, you should be able to see if in fact there is a difference in your two populations.
For our green bean example, our conclusion would be as follows:
Since our p value is essentially 0 and less than 0.05, we reject our Ho. We have convincing evidence that the true mean number of green beans picked from Field A differs from that picked in Field B.
I made sure to compare our p-value to our significance level, reject/fail to reject Ho, and have evidence/not have evidence of the Ha. Also, my answer is in context.